If a flexible air-filled container has a volume of 40 cu ft on the surface, what would its volume be at 99 feet in sea water (rounded off)?

To determine the volume of a flexible air-filled container at a depth of 99 feet in seawater, it is important to understand how pressure affects volume according to Boyle's Law, which states that for a given mass of gas at constant temperature, the pressure and volume of a gas are inversely proportional.

At sea level, the pressure is approximately 1 atmosphere (atm), and as you descend underwater, the pressure increases by approximately 1 atm for every 33 feet of seawater due to the weight of the water above. Therefore, at 99 feet, the total pressure experienced by the container is roughly 4 atm (1 atm from the atmosphere plus 3 atm from the water).

Using Boyle's Law, the equation can be expressed as:

P1 * V1 = P2 * V2

Where:

• P1 is the initial pressure (1 atm at the surface).

• V1 is the initial volume (40 cu ft on the surface).

• P2 is the pressure at 99 feet (4 atm).

• V2 is the volume at 99 feet.

Rearranging Boyle's Law to solve for V2 gives:

V2 = (P1 * V1) / P2

V2 =